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Vladimir [108]
3 years ago
15

Find all critical values of the function g(x)=5/(x²-x+6)

Mathematics
1 answer:
Sati [7]3 years ago
3 0
g(x)=\frac{5}{x^2-x+6}\\\\D:x^2-x+6\neq0\\\\\Delta=(-1)^2-4\cdot1\cdot6=1-24=-23 < 0\\\\x\in\mathbb{R}\\\\vertex\ of\ y=x^2-x+6\\\\p=\frac{-(-1)}{2\cdot1}=\frac{1}{2}\\\\q=\frac{-(-23)}{4\cdot1}=\frac{23}{4}\\\\\lim\limits_{x\to\frac{1}{2}}\frac{5}{x^2-x+6}=\frac{5}{\frac{23}{4}}=\frac{5\cdot4}{23}=\frac{20}{23}

\lim\limits_{x\to\pm\infty}\frac{5}{x^2-x+6}=0

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Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

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                                       x+DB = 3

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Since given AD=BC,let us plugin BC=x in above step.

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Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

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