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Stella [2.4K]
3 years ago
5

Circle 1: center (8, 5) and radius 6

Mathematics
1 answer:
PolarNik [594]3 years ago
6 0
We have that
<span>Circle 1: center (8, 5) and radius 6
</span><span>Circle 2: center (−2, 1) and radius 2

we know that
the equation of a circle is
(x-h)</span>²+(y-k)²=r²
for the circle 1---------> (x-8)²+(y-5)²=36
for the circle 2---------> (x+2)²+(y-1)²=4

using a graph tool 
see the attached figure

Part A)<span>What transformations can be applied to Circle 1 to prove that the circles are similar?

we know that
r1/r2---------> 6/2------> 3
</span><span>
to prove that the circle 1 and circle 2 are similar, the radius of circle 1 </span>must be divided by 3 and  translate the center of the circle 1  (10) units to the left and (4) units down  
<span>
 the answer part A) is
</span>the radius of circle 1 must be divided by 3 and  translate the center of the circle 1  (10) units to the left and (4) units down  


Part B) <span>What scale factor does the dilation from Circle 1 to Circle 2 have?

the answer Part B) is 
the scale factor is (3/1)</span>

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Answer:

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Step-by-step explanation:

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We can use the Polynomial Remainder Theorem. According to the PRT, if we have a polynomial P(x) being divided by a binomial in the form (<em>x</em> - <em>a</em>), then the remainder will be given by P(a).

Here, our divisor is (<em>x</em> + 4). We can rewrite this as (<em>x</em> - (-4)).

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