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2 years ago

PLEASE HELPWhich line has an equation of Y-5X+4 in slope-intercept form?

Mathematics

1 answer:

alekssr [168]2 years ago

6 0

Answer:

a line passing through the points (2, -6) and (4, -16)

Step-by-step explanation:

y=-5x+4

you plug in the x value and put the y value on the left side of the equation

for example

-6 = -5(2) + 4

then solve to see if it works

-5(2) = -10 + 4 = -6

(2, -6) works

-16 = -5(4) +4

-5(4) = -20

-20 + 4 = -16

(4, -16) works

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Maksim231197 [3]

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3 years ago

sweet-ann [11.9K]

Answer:

3. 3 : 5; 3: 5

Step-by-step explanation:

First, let's find the leght of the sides of each octagon.

$A= 18in^{2}$

The area of an octagon is defined by

$A=2(1+\sqrt{2})l^{2}$

Replacing the area

$18=2(1+\sqrt{2})l^{2}\\\frac{18}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{18}{3.4} } \approx 2.3 \ in$

Therefore, the side of the first octagon is 1.6 inches long.

Its perimeter is: $P=8(2.3in)=18.4in$

$A=50 in^{2}$

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Therefore, the side of the second octagon is 3.8 inches long.

Its perimeter is $P=8(3.8in)=30.4in$ .

Now, let's divide to find each ratio:

$\frac{3.8}{2.3} \approx 1.65$ (the ratio between sides).

$\frac{30.4}{18.4} \approx 1.65$ (the ratio between perimeters).

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2 years ago

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