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kiruha [24]
3 years ago
11

What is the simplest form of

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Step-by-step explanation:

step 1. the cube root is also to the 1/3 power

step 2. (27a^3b^7)^(1/3) = (3*3*3*a*a*a*b*b*b*b*b*b*b)^(1/3)

step 3. a third root: 3 factors in the root comes "out" of the root as 1

step 4. 3ab*b(b)^(1/3) = 3ab^2(b)^(1/3).

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The height is 5 and 1/4 then the base is 2 and 1/2

You can convert these fractions into decimals and them multiply them to get your area.
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Someone help me out ​
Alexeev081 [22]
It’s B because I got it right
7 0
3 years ago
Can you guys please do both with the work please and thank you if you actually do it
salantis [7]

Answer:

  7.  29 cm

  8.  equation: 61 = (x) +(2x -7) +(3x +2); sides 11, 15, 35

Step-by-step explanation:

7. Let w represent the width. The length is 3 less than twice the width, so the length is 2w-3. The perimeter is given by the formula ...

  P = 2(L+W)

Substituting the known values, we have ...

  90 = 2((2w-3) +w)

  45 = 3w -3 . . . . . . . . divide by 2

  15 = w - 1 . . . . . . . . . .divide by 3

  16 = w . . . . . . . . . . . . add 1

  L = 2w -3 = 2(16) -3 = 29

The length of the rectangle is 29 cm.

__

8. The equation that should be used is the one that relates the side lengths to the perimeter.

  P = a + b + c . . . . for sides a, b, c

  61 = (x) +(2x -7) +(3x +2)

  61 = 6x -5 . . . . . . collect terms

  66 = 6x . . . . . . . . add 5

  11 = x . . . . . . . . . . divide by 6

Then the side lengths are ...

  a = x = 11

  b = 2x -7 = 2(11) -7 = 15

  c = 3x +2 = 3(11) +2 = 35

_____

<em>Comment on problem 8</em>

You will notice that the side lengths do not satisfy the triangle inequality: the sum of the short sides is not greater than the long side. <em>These side lengths cannot form a triangle</em>. Cute algebra, but <em>bad geometry</em>.

4 0
3 years ago
Find the values of which satisfy the equation. 2 cos (2B+30°) = -√3 in the domain OP ≤B≤360°​
PSYCHO15rus [73]

Answer:

60 and 90

Step-by-step explanation:

2 \cos(2 \beta  + 30)  =  -  \sqrt{3}

\cos(2 \beta  + 30)  =  -  \frac{ \sqrt{3} }{2}

2 \beta  + 30 =  \cos {}^{ - 1} ( \frac{   -   \sqrt{3} }{2} )

First solution.

2 \beta  + 30 = 150

2 \beta  = 120

\beta  = 60

Second solution

2 \beta  + 30 = 210

2 \beta  = 180

\beta  = 90

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2 years ago
2492 divided by 4 in long division
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Well all I can say is that the answer is 623
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