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kiruha [24]
3 years ago
11

What is the simplest form of

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Step-by-step explanation:

step 1. the cube root is also to the 1/3 power

step 2. (27a^3b^7)^(1/3) = (3*3*3*a*a*a*b*b*b*b*b*b*b)^(1/3)

step 3. a third root: 3 factors in the root comes "out" of the root as 1

step 4. 3ab*b(b)^(1/3) = 3ab^2(b)^(1/3).

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The figure shows a rectangle with a width of 6k inches. The length of the rectangle is 4 inches shorter than the width.
Aliun [14]

Step-by-step explanation:

b. what is the perimeter of the rectangle in terms of k?

4 0
3 years ago
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Sarah went to the mall and bought a pair of sneakers for $132. They are on sale for 20% off. What will the new price be?
qaws [65]

Answer:

$105.6

Step-by-step explanation:

132*.20=26.4

132-26.4=105.6

3 0
3 years ago
(Prove) The angle subtended by an arc at the center is double the angle subtended by it at any
Pavlova-9 [17]

Answer:

The angle subtended by an arc at the center is double the angle subtended by it at any  point on the remaining part of the circle.

Step-by-step explanation:

Let us consider the image attached.

Center of circle be O.

Arc AB subtends the angle \angle APB on the circle and \angle AOB on the center of the circle.

To prove:

\angle AOB = 2 \times \angle APB

Proof:

In \triangle PAO: AO and PO are radius of the circles so AO = PO

And angles opposite to equal sides of a triangle are also equal in a triangle.

So, \angle PAO = \angle OPA

Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

\angle AOQ = \angle PAO + \angle OPA=2 \times \angle APO .... (1)

Similarly,

In \triangle PBO: BO and PO are radius of the circles so BO = PO

And angles opposite to equal sides of a triangle are also equal in a triangle.

So, \angle PBO = \angle OPB

Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

\angle BOQ = \angle PBO + \angle OPB=2 \times \angle BPO .... (2)

Now, we can see that:

\angle AOB = \angle AOQ+\angle BOQ

Using equations (1) and (2):

\angle AOB = 2\angle APO+2\angle BPO\\\angle AOB = 2(\angle APO+\angle BPO)\\\bold{\angle AOB = 2(\angle APB)}

Hence, proved.

4 0
3 years ago
Determine the volume of a cylinder if its height is 5mm and a radius of 12mm​
Elenna [48]

Answer:

Step-by-step explanation:

V = pi * r^2 * h

r = 12 mm

h = 5 mm

pi = 3.14

V= 3.14 * 12^2 * 5

V = 3.14 * 144 * 5

V = 2260.8 cm^3

3 0
3 years ago
I REALLY REALLY NEED HELP!!! CANT FIGURE THIS OUT!! GIVING BRAINLIEST TO BEST ANSWER! IM DESPERATE!!
Deffense [45]

Here is a story problem that can go with this:

There was \frac{3}{4} of the cake left after the party. Matthew ate \frac{2}{6} of the leftover cake. How much of the cake did Matthew have?

5 0
2 years ago
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