<h2><u>
Answer with explanation</u>
:</h2>
Let 
be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since 
is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For 
, we have
By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
Answer:
837150
/7
Step-by-step explanation:
459(
569
/7
)+997
=
830171
/7
+997
=
837150
/7
40 x 0.08875 = 3.55
40 + 3.55 = 43.55
the sum is $43.55
Answer:
3/5
Step-by-step explanation:
To make 0.6 as a fraction (you can't make it a mixed number because there is no number to the left of the point) place a 1 under it to make it a fraction:
0.6/1
Since you can't have a decimal on a fraction, multiply by 10;
0.6/1 × 10/10 =6/10
Simply your answer (6/10) to get 3/5
