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3 years ago

Write the slope-intercept form of the line that passes through the point (1, 0) and is parallel to x - y = 7.

1 answer:

3 0

If it's parallel to x - y = 7, that means the slope of that equation is the slope for the equation you're looking for. To get the slope, you need to put the given equation into slope intercept form, so move x to the other side. You should get: -y = 7 - x Then, to get the y positive, divide by -1: y = -7 + x Slope intercept form is as follows: y = mx + b, so whatever the number is in front of x is your slope. In this instance, your slope is 1. You now have your slope, and a point in which your new line passed through. Using slope intercept form, y = mx + b, if you substitute in what you know, you can find your answer. Right now you know y, m, and x, and you're looking for b. x=1; y=0; m=1. So, substituting, you'd get 0 = (1)(1) + b 0=1+b Solve You should get b= -1, leaving your final answer as y = x - 1

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If cp=rs 400, loss=10% find sp

Shalnov [3]

Answer:

cp = rs 400

loss = 10%

Then SP = 400 - 10% of 400

= 400 - 40

= 360

Therefore SP = Rs. 360

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1 year ago

The label on a \frac{1}{4}

alexgriva [62]

Answer:

$183.63$ square feet area is covered by seeds per pound

Step-by-step explanation:

Given

$41\frac{1}{4}$ pound bag of seed cover an area of $7575$ square feet

$\frac{165}{4}$ pound bag of seed cover an area of $7575$ square feet

$7575$ square feet area is covered by $\frac{165}{4}$ pound bag of seed

Area in square feet covered by one pound bag of seed

$= \frac{7575}{\frac{165}{4} } \\= \frac{7575 * 4}{165} \\= 183.63$ square feet

4 0

3 years ago

(x-4) ( x-4)=0 explain , step by step please

Ganezh [65]

Answer:

x = 4

Step-by-step explanation:

Step 1: Set both parts equal to 0

x - 4 = 0 and x - 4 = 0

Step 2: Solve for x by adding 4 to both sides

x - 4 + 4 = 0 + 4 and x - 4 + 4 = 0 + 4

x = 4 and x = 4

Answer: x = 4

3 0

3 years ago

Read 2 more answers

Logb sqrt 29/61 Is it logb (29-61)?? am i right

Fiesta28 [93]

Answer:

$log_b{\sqrt{\frac{29}{61}}=log_b(\sqrt{29}-\sqrt{61}})$

Step-by-step explanation:

We have been given the expression:

$log_b{\sqrt{\frac{29}{61}}$

We will use the property:

$log_a{\frac{n}{m}}=log_a{m-n}[$

Here, $a=b,n=\sqrt{29}\text{and}m=\sqrt{61}$

So, we will get from the identity:

$log_b{\sqrt{\frac{29}{61}}=log_b(\sqrt{29}-\sqrt{61})$

Hence, you are not right because you removed square rrot in final result rest is right.

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3 years ago

Read 2 more answers

Help me please please please please

Sophie [7]

Not sure what the question is, but the equation for this graph would be 2|x-1|+1
the equation is usually a|x-h|+k
a is the slope (rise over run) and this goes up (rise) 2 every time it moves 1 left (run) so the slope is 2/1 which is just 2
then the x is kept the same and h is how much left or right the origin is, this one is 1 to the right so it's minus 1 (left would be plus one)
the k is how much up or down the origin is
this one is 1 up, so +1

3 0

3 years ago