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raketka [301]
3 years ago
15

Create the equation to the parallel or perpendicular lines. Describe the transformation(s).:

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

Answer:

.

Step-by-step explanation:

.

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An article reports the following data on yield (y), mean temperature over the period between date of coming into hops and date o
skelet666 [1.2K]

Answer:

x1=c(16.7,17.4,18.4,16.8,18.9,17.1,17.3,18.2,21.3,21.2,20.7,18.5)

x2=c(30,42,47,47,43,41,48,44,43,50,56,60)

y=c(210,110,103,103,91,76,73,70,68,53,45,31)

mod=lm(y~x1+x2)

summary(mod)

R output: Call:

lm(formula = y ~ x1 + x2)

Residuals:  

   Min      1Q Median      3Q     Max

-41.730 -12.174   0.791 12.374 40.093

Coefficients:

        Estimate Std. Error t value Pr(>|t|)    

(Intercept) 415.113     82.517   5.031 0.000709 ***  

x1            -6.593      4.859 -1.357 0.207913    

x2            -4.504      1.071 -4.204 0.002292 **  

---  

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1  

Residual standard error: 24.45 on 9 degrees of freedom  

Multiple R-squared: 0.768,     Adjusted R-squared: 0.7164  

F-statistic: 14.9 on 2 and 9 DF, p-value: 0.001395

a).  y=415.113 +(-6.593)x1 +(-4.504)x2

b). s=24.45

c).  y =415.113 +(-6.593)*21.3 +(-4.504)*43 =81.0101

residual =68-81.0101 = -13.0101

d). F=14.9

P=0.0014

There is convincing evidence at least one of the explanatory variables is significant predictor of the response.

e).  newdata=data.frame(x1=21.3, x2=43)

# confidence interval

predict(mod, newdata, interval="confidence")

#prediction interval

predict(mod, newdata, interval="predict")

confidence interval

> predict(mod, newdata, interval="confidence",level=.95)

      fit      lwr      upr

1 81.03364 43.52379 118.5435

95% CI = (43.52, 118.54)

f).  #prediction interval

> predict(mod, newdata, interval="predict",level=.95)

      fit      lwr      upr

1 81.03364 14.19586 147.8714

95% PI=(14.20, 147.87)

g).  No, there is not evidence this factor is significant. It should be dropped from the model.

4 0
3 years ago
How could I write the fractions 1/2 2/5 6/10 from least to greatest
guapka [62]
1/2=5/10
2/5=4/10
6/10
so from least to greatest will be : 2/5 1/2 6/10  :)))))
6 0
3 years ago
While riding her bike to the ocean and back home 5 times, Kimberly timed herself at 53min, 48min, 56min, 54min, and 45min. She h
alex41 [277]

Answer:

Kim will need to spend 67 minutes on her sixth ride

Step-by-step explanation:

Represent the number of minutes of her sixth ride by m.

Then the average number of minutes is

53 + 43 + 56 + 54 + 45 + m

---------------------------------------- = 53

                      6

Multiplying both sides of this equation by 6 yields

6(53 + 43 + 56 + 54 + 45 + m)

--------------------------------------------- = 6(53)

                        6

which simplifies to

 251 + m

---------------- = 318

         

or  251 + m = 318.  Subtract 251 from both sides to obtain the value of m:

m  = 318 - 251 = 67

Kim will need to spend 67 minutes on her sixth ride to attain an average ride length of  53 minutes.i

4 0
2 years ago
What is the slope of this line?
icang [17]
Y = 2
slope = 0

hope it helps
7 0
3 years ago
Read 2 more answers
what is the best approximation of the solution to the system to the nearest valus 2x-3y=-6 and x+2y=8
Trava [24]
Given:
2x - 3y = -6  ⇒ identified as 1st equation
x + 2y = 8    ⇒ identified as 2nd equation

Let us first get the value of x using the 2nd equation.
x + 2y = 8
x = 8 - 2y

Substitute x in the 1st equation with its value and find the value of y.
2x - 3y = -6
2(8-2y) - 3y = -6
16 - 4y -3y = -6
-4y - 3y = -6 -16
-7y = - 22
y = -22/-7
y = 22/7 simplified to 3 1/7

Substitute the value of y in the 2nd equation.
x = 8 - 2y
x = 8 - 2(22/7)
x = 8 - 44/7
x = (8 * 7/7) - 44/7
x = 56/7 - 44/7
x = (56-44)/7
x = 12/7 simplified to 1 5/7

To check:  x = 12/7 and y = 22/7  *we need to use the improper fractions.
2x - 3y = -6
2(12/7) - 3(22/7) = -6
24/7 - 66/7 = -6
(24-66)/7 = -6
-42/7 = -6
-6 = -6

x + 2y = 8
12/7 + 2(22/7) = 8
12/7 + 44/7 = 8
(12+44)/7 = 8
56/7 = 8
8 = 8

8 0
3 years ago
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