F(x)=-4x-2
F(x)=-4(-1)-2
F(x)=4-2
F(x)=2
F(x)=-4x-2
F(x)=-4(0)-2
F(x)=0-2
F(x)=-2
F(x)=-4x-2
F(x)=-4(1/2)-2
F(x)=-8-2
F(x)=-10
I hope this helps!!
A in the answer for this question
Thank you
Answer:
Step-by-step explanation:
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
