2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi
1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi
Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
Area Rectangle 2 = 280 mi * 170 mi = 47,600 mi²
Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²
Total Area = 6,400 mi² + 47,600 mi² + 9,800 mi² = <span>63,800 mi²</span>
Step-by-step explanation:
For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,
b^2 - 4ac must be positive.
b^2 - 4ac > 0
(k - 3)^2 - 4(3 - 2k) > 0
k^2 - 6k + 9 - 12 + 8k > 0
k^2 + 2k - 3 > 0
Answer:
D. y²/5² - x²/8² = 1
Step-by-step explanation:
A and B are both incorrectly oriented, and D is the only hyperbola that contains the points (0,5) and (0,-5).
Verification (0,5) and (0,-5) are in the hyperbola:
First replace x and y with corresponding x and y values (We will start with x=0 and y=5)
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Then simplify.



If the result is an equation (where both sides are equal to each other) then the original x and y values inputted are valid. The same is true with x and y inputs x=0 and y=-5, or any other point along the hyperbola.
A) 70/130*100 = 53.8 %
B) 30/40 = 3/4 = 0.75
hope you have a great day !
12*2+7(x) you need to solve for x