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2 years ago

Which of the following is not a solution to the inequality graphed below?

Mathematics

1 answer:

Irina18 [472]2 years ago

8 0

Answer:

C ( 1,-2)

Step-by-step explanation:

We can plot the points and see what point is not in the shaded section

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6(5 + 3x) is equivalent too

Artyom0805 [142]

Answer:

30+18 x

Step-by-step explanation:

5 0

2 years ago

Sarah starts with $375 in her savings account. After getting a part-time job, she deposits $90 every week. Write an equation sho

Valentin [98]

Answer:

y = 375 + 90x is the equation

4 0

3 years ago

La empresa los manzanas exporta manzanas o varios paises del mundo, el lunes tiene que trasladar 300 cajones. Puede contratar ca

Mariulka [41]

Answer:

Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.

Step-by-step explanation:

Dada la siguiente información:

Cantidad de cajones= 300

Opción A:

Camiones con capacidad para 50 cajones que cobran 150 por viaje.

Cantidad de camiones= 300/50= 6

Opción B:

Camiones con capacidad de 60 cajones por 180 por viaje.

Cantidad de camiones= 300/60= 5

Debemos calcular el costo total de cada opción y elegir la de menor costo.

Costo total A= 150*6= $900

Costo total B=180*5= $900

Para trasladar 300 cajones, las dos opciones cuestan los mismo. Son indiferentes entre si.

5 0

2 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

Alternative method

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago

11x - 2x + 15 = 8 + 7 + 9x Help please

sergey [27]

Answer:

15 it's in the equation

Step-by-step explanation:

11x-2x=9x 9x-9x=0

7+8=15

8 0

3 years ago

Read 2 more answers