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4 years ago

Help please I will really love that

Mathematics

1 answer:

Vsevolod [243]4 years ago

6 0

If there's only 1 table, then you need 5 roses total (5*1 = 5)

If there are 2 tables, then you need 10 roses total (5*2 = 10)

If there are 3 tables, then you need 15 roses total (5*3 = 15)

If there are 4 tables, then you need 20 roses total (5*4 = 20)

At this point, you probably see the pattern: you multiply 5 by the number of tables to get the total number of roses. So it would look like this equation

(number of roses) = 5*(number of tables)

r = 5*x

where r is standing in for "number of roses" as shorthand; also, x is standing in for "number of tables".

------------------------------------------------------------------------

Final Answer: r = 5x (lower right corner choice)

Note that 5*x is the same as 5x (both of which mean "5 times x)

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Julia uses the shadow of a flagpole to estimate its height. She stands so that the tip of her shadow coincides with the tip of t

Sliva [168]

The flag pole is 25 feet tall,
The ratio of between Julia is 5ft(height)/ 7 ft(length of shadow)
The flag pole is x/35 feet. Cross multiply 5x35=7x to get 25

5 0

3 years ago

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Oksanka [162]

Answer:

$9$

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3 years ago

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What is the Least Common Multiple for 6 and 8?

VladimirAG [237]

Answer:

Step-by-step explanation:

The multiples of 8 are 8,16,24,32 etc. and the multiples of 6 are 6,12,18,24,30, ect. The answer is 24 because it is the lowest multiple of 6 that crosses with multiples of 8.

7 0

3 years ago

NEED HELP ASAP!!

galina1969 [7]

The distance of the ship from the lighthouse can be determined using

trigonometric ratios.

The ship's horizontal distance from the lighthouse is approximately 1,303.03 feet.

Reasons:

The given parameters are;

The height of the beacon-light above the ground = 114 feet

The angle of elevation to the beacon measured by the boat crew = 5°

Required:

The horizontal distance of the ship from the lighthouse

Solution:

The beacon-light that is seen by the boat crew, the height of the beacon light, and the horizontal distance of the ship from the lighthouse form a right triangle.

Therefore, we have;

$\displaystyle tan (\theta) = \mathbf{ \frac{Opposite}{Adjacent}}$

$\displaystyle tan(angle \ of \ elevation) = \mathbf{\frac{Height \ of \ beacon \ light}{The \ ship's \ horizontal \ distance \ from \ the \ lighthouse}}$

Which gives;

$\displaystyle The \ ship's \ horizontal \ distance \ from \ the \ lighthouse= \frac{Height \ of \ beacon \ light}{tan(angle \ of \ elevation)}$

Therefore;

$\displaystyle The \ ship's \ horizontal \ distance \ from \ the \ lighthouse= \frac{114 \ feet}{tan(5^{\circ})} \approx \mathbf{1,303.03 \ feet}$