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Mama L [17]
3 years ago
11

Find the slope of the line that passes through the points (4, 3) and (2, 7).

Mathematics
1 answer:
timofeeve [1]3 years ago
5 0

Answer:

-2

Step-by-step explanation:

7-3/2-4=-2

use slope formula

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Use the zero product property to find the solutions to the equation x^2-15x-100=0
Helen [10]

Answer:

It’s c

Step-by-step explanation:

5 0
2 years ago
If it takes one minute to run 130 meters how long will it take to run 1494.23 meters
Rus_ich [418]
We have to see how many times 130 fits into 1494.23:

1494.23/130=11.4940....

So now we have to multiply this by the amount of time needed for 130 meters:
11.4940*1=11.4940.

So the answer is 11.4940 minutes.


4 0
3 years ago
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Which is the best estimate for the quotient of 198.32 ÷ 9.001?
Whitepunk [10]
I would believe it to be 22
4 0
3 years ago
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You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o
anyanavicka [17]

Answer:

x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

=\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0

-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0

\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}

squaring both sides; we get

\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}

\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}

By cross multiplying; we get

49x^2 = 25(54^2+x^2)

49x^2 = 25 \times 54^2+ 25x^2

49x^2-25x^2 = 25 \times 54^2

24x^2 = 25 \times 54^2

x^2 = \dfrac{25 \times 54^2}{24}

x =\sqrt{ \dfrac{25 \times 54^2}{24}}

x =\dfrac{5 \times 54}{\sqrt{24}}

x =\dfrac{270}{\sqrt{4 \times 6}}

x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}

x =\dfrac{45 \sqrt{6}}{ 2}

8 0
3 years ago
Which point is an x-intercept of the quadratic equation (x-8)(x+9)
defon

Solve for x in each set of parentheses by setting them to 0:

X -8 = 0

X = 8

X+9 = 0

X =-9

You have two x intercepts (8,0) and (-9,0)

You didn’t list any choices to pick from but it would be either if the ones above.

5 0
2 years ago
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