Answer:
x = 23; not extraneous
Step-by-step explanation:
A solution is extraneous if it does not satisfy the original equation. Extraneous solutions can sometimes be introduced in the process of solving radical and rational function equations.
<h3>Solution</h3>
Squaring both sides of the given equation, we get ...
√(3x +12) = 9
3x +12 = 81 . . . . . . square both sides
x +4 = 27 . . . . . . . divide by 3
x = 23 . . . . . . . . . . subtract 4
<h3>Check</h3>
There is only one solution, and it satisfies the equation:
√(3×23 +12) = √81 = 9
The solution x = 23 is not extraneous.
Answer:
The solution to the equation is as follows;
Step-by-step explanation:
Given;
5x - 3y = 1
3x + 2y = 1
Solving both equation simultaneously;
2: 10x - 6y = 2
3: 9x + 6y = 3
--------------------------
19x + 0 = 5
x = 5/19
substitute the value of x in any of the equations above and solve for y;
5x - 3y = 1
5 (5/19) - 3y = 1
25/19 -3y = 1
{ y = 4 - x
y = x - 4
Subsititute y = x - 4
[ ( x - 4 )] = 4 - x ]
isolate x for ( x - 4 ) = 4 - x
x = 4
For y = x - 4
Subsititute<span> x = 4
</span>
y = 4 - 4
y = 0
Solution
x = 4 and y = 0
hope this helps!
Answer:
25% decrease
Step-by-step explanation:
