<h3>Radius = 14cm</h3>
Step-by-step explanation:
Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC
Also, AD ⊥ DC (given), therefore, OPDS is a square.
BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)
therefore, CR = CB - BR = (38 - 27)cm = 11cm
SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.
therefore,
Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).
<h3>Hope it helps you!! </h3>
Answer:
x = 4 ±√26
Step-by-step explanation:
Please write this as x^2 - 8x = 10, or x^2 - 8x - 10 = 0. " ^ " indicates exponentiation.
Let's complete the square:
x^2 - 8 x can be rewritten as
x^2 - 8x + 16 - 16, and so
x^2 - 8x = 10 becomes x^2 - 8x + 16 - 16 - 10 = 0, or
(x - 4)^2 = 26
Taking the square root of both sides, we get:
x - 4 = ±√26, or
x = 4 ±√26
Answer:
the answer is c
Step-by-step explanation:hope this helped!
The answer is B: (-1/4, 1/2)
