Express the given quantity as a single logarithm. ln x + a ln y − b ln z

1 answer:

6 0

The rules of logarithms tell you ...
• $\ln(a)+\ln(b)=\ln(a \cdot b)$
• $a \cdot \ln(b)=\ln(b^{a})$

$\ln(x)+a \cdot \ln(y)-b \cdot \ln(z)=\ln\left( \dfrac{x \cdot y^{a}}{z^{b}} \right)$

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Tomtit [17]

Answer:

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Step-by-step explanation:

Step I

The formula is given as

$C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}$