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Answer:
d
Step-by-step explanation:
Since DF = EF then the triangle is isosceles with base angle being congruent, that is
∠ D = ∠ E , then
∠ D = =
= 23.5°
Step 1) Draw a dashed line through the points (0,6) and (4,7). These two points are on the line y = (1/4)x+6. To find those points, you plug in x = 0 to get y = 6. Similarly, plug in x = 4 to get y = 7. The dashed line indicates that none of the points on this line are part of the solution set.
Step 2) Draw a dashed line through (0,-1) and (1,1). These two points are on the line y = 2x-1. They are found in a similar fashion as done in step 1.
Step 3) Shade the region that is above both dashed lines. We shade above because of the "greater than" sign. This is shown in the attached image I am providing below. The red shaded region represents all of the possible points that are the solution set. Once again, any point on the dashed line is not in the solution set.
Step 2) Draw a dashed line through (0,-1) and (1,1). These two points are on the line y = 2x-1. They are found in a similar fashion as done in step 1.
Step 3) Shade the region that is above both dashed lines. We shade above because of the "greater than" sign. This is shown in the attached image I am providing below. The red shaded region represents all of the possible points that are the solution set. Once again, any point on the dashed line is not in the solution set.
Answer:
6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45
7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6
8. B+ to total donors = 20 to 195; 20 : 195 and 20/195
9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21
10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20
11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195
12. A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6
13. A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4
14. the ratio 90/9 is a comparison of O+ donors to O- donors
Step-by-step explanation:
A ratio is a relationship where for every x unit of one quantity there are y units of another quantity. A ratio can be written in three ways:
x to y
x:y, or
x/y
For the given questions;
6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45
7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6
8. B+ to total donors = 20 to 195; 20 : 195 and 20/195
9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21
10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20
11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195
12. A+ donors and B+ donors to AB+ donors
A+ donors and B+ donors to = 45 + 20 = 65
therefore, A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6
13. A- donors and B- donors to AB- donors
A- donors and B- donors = 21 + 0= 21
therefore, A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4
14. O+ donors = 90; O- donors = 9
therefore, the ratio 90/9 is a comparison of O+ donors to O- donors
