Answer:
(-2, 1) and (0, 3) has the slope of m = 1 and the equation is y = x + 3
(0, -2) and (3, -5) has the slope of m = 1 and the equation is y = -x - 2
Step-by-step explanation:
Hope this helps!
Answer:
0.101
Step-by-step explanation:
Given that :
Standard deviation, s = 0.2
Sample variance, s² = 0.0653
Sample size, n = 10
Population variance = σ² = 0.04
We use the Chi square distribution :
(n - 1)s² / σ²
For P(s² ≥ 0.065)
(n - 1)s² / σ² = (10 - 1)*0.0653 / 0.04
(n - 1)s² / σ² = 0.585 / 0.04 = 14.625
P(s² ≥ 14.625) = 0.101 ( chi squee calculator).
Answer:
6:$255.50
7:$21.25
8:$219.50
9:$143.75
Step-by-step explanation:
Can i have brainiest?!!!!
Is z an angle? if so, i'll use the ration
[email protected]=perpendicular/base
tanZ=15/20=3/4 answer
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
