Answer:
5x5 is 25 and 5+5+5+5+5 is also 25 please give brainliest
Step-by-step explanation:
Answer:
![4x + 13](https://tex.z-dn.net/?f=4x%20%2B%2013)
Step-by-step explanation:
first solve the first part then subtract it from the other part.
![(2x + 8)2 = 4x + 16](https://tex.z-dn.net/?f=%282x%20%2B%208%292%20%3D%204x%20%2B%2016)
that is the first part.
the second part solve it too.
![8 \times 2 - 3 = 13](https://tex.z-dn.net/?f=8%20%5Ctimes%202%20-%203%20%3D%2013)
so put it all together
![4x + 16 - 13 = 4x + 13](https://tex.z-dn.net/?f=4x%20%2B%2016%20-%2013%20%3D%204x%20%2B%2013)
3-2= -3x-x
1 = -4x
x = -1/4
Yes it is possible
Answer:
The distance between parallel lines is ![0.6860\ units](https://tex.z-dn.net/?f=0.6860%5C%20units)
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Line A and Line B are parallel lines, because their slopes are equal
Step 1
Find the slope of the given lines
isolate the variable y in the equation A
![5y=3x-1](https://tex.z-dn.net/?f=5y%3D3x-1)
![y=(3/5)x-1/5](https://tex.z-dn.net/?f=y%3D%283%2F5%29x-1%2F5)
The slope is ![m=(3/5)](https://tex.z-dn.net/?f=m%3D%283%2F5%29)
Step 2
Find the slope of the perpendicular line to the given lines
we know that
If two lines are perpendicular, then the product of their slopes is equal to -1
so
![m1*m2=-1](https://tex.z-dn.net/?f=m1%2Am2%3D-1)
we have
-----> given lines
substitute
![(3/5)*m2=-1](https://tex.z-dn.net/?f=%283%2F5%29%2Am2%3D-1)
Step 3
Find the equation of the perpendicular line that pass though the origin
with the slope
and the point (0,0) Find the equation of the line
![y-y1=m(x-x1)](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29)
![y-0=(-5/3)(x-0)](https://tex.z-dn.net/?f=y-0%3D%28-5%2F3%29%28x-0%29)
![y=-(5/3)x](https://tex.z-dn.net/?f=y%3D-%285%2F3%29x)
Step 4
Using a graphing tool
Graph the two parallel lines and the perpendicular line
The intersection points are
and
see the attached figure
we know that
the distance between the points A and B is the distance between parallel lines
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
substitute the values
![d=\sqrt{(-0.1471-0.4412)^{2}+(0.0882+0.2647)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-0.1471-0.4412%29%5E%7B2%7D%2B%280.0882%2B0.2647%29%5E%7B2%7D%7D)
![d=\sqrt{(-0.5883)^{2}+(0.3529)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-0.5883%29%5E%7B2%7D%2B%280.3529%29%5E%7B2%7D%7D)
![d=0.6860\ units](https://tex.z-dn.net/?f=d%3D0.6860%5C%20units)