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2 years ago

Simplify the radical.

Mathematics

1 answer:

Tanya [424]2 years ago

3 0

I think the answer is Dtell me if I’m wrong

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What value of x is in the solution set of –2(3x + 2) > –8x + 6? –6 –5 5 6

Assoli18 [71]

Answer: X=6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Is 2 a solution to the equation 1/2x-4=5?

dusya [7]

9514 1404 393

Answer:

Step-by-step explanation:

Put 2 where x is and see if you get a true statement.

1/2(2) -4 = 5

1 -4 = 5

-3 = 5 . . . . . . False

2 is not a solution to the equation.

The solution is x=18.

6 0

2 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

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2 years ago

Write an inequality that represents each sentence.

ivann1987 [24]

1. Julia's ≤ Rachel's hair

2. 40 < 74

7 0

3 years ago

What is the average rate of change for this function for the interval from x=3 to x=5?

SSSSS [86.1K]

Answer:

A. 49

Step-by-step explanation:

The average rate of change for the interval ranging from x = 3 to x = 5 for the given function represented in the table above can be calculated using:

$Average rate of change = \frac{f(x2) - f(x1)}{x2 - x1}$