9514 1404 393
Answer:
nπ -π/6 . . . for any integer n
Step-by-step explanation:
tan(x) +√3 = -2tan(x) . . . . . given
3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3
tan(x) = -√3/3 . . . . . . . . . . divide by 3
x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x
This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...
x = n·π -π/6 . . . . for any integer n
Answer:
$894
Step-by-step explanation:
0.06 x 500 x 8^1.25 (-9)= 500+ 403 = $903-9= $894
1.25 = 1/8 of 1 (-9)
1=each power.
8th year = $843.75
9th year = $894
Semi annually you can do the same as 16/1 -17
Answer:
MN=23
Step-by-step explanation:
For the midsegment:
MN=(WZ+XY)/2
10x+3=(11+8x+19)/2
10x+3=4x+15
6x=12
x=2
MN=10×2+3=23
Answer:
A) -12-4-5
B) X^2-X
Step-by-step explanation:
..
..
7x + 5 = 2x - 35
=> 7x - 2x = - 35 - 5
=> x( 7 - 2 ) = - ( 35 + 5 )
=> x( 5 ) = - ( 40 )
=> x × 5 = - 40
x = 5
Therefore the value of x in the given equation 5
