All categories

3 years ago

Please help with 1,2, and 3

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

Answer:

The slope is 0.9

Step-by-step explanation:

You'll want to start by labeling the points at (1,2.3) and at (6,6.8) which is the first pairs that you are given. You'll want to find use the formula to find the rise and the run which I'll give

(6.8-2.3)/(6-1) which is 4.5/5 which is 0.9

So for each week you'll make a total of 0.9 million dollars.

Give me some more time to do the other questions.

You might be interested in

A man weekly pay is $x. he spends 1/2 of his pay on food and 1/3 on rent

vekshin1

answer 40qfijjjjjmwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwStep-by-step explanation:

7 0

3 years ago

Which category do all of these shapes belong to?<br> Help

lukranit [14]

Those shapes are all rectangle

8 0

3 years ago

Read 2 more answers

What property describes the number sentence? 6+0=6

nikklg [1K]

The zero property of addition describes 6+0=6.

7 0

3 years ago

What is the angle of a in the above scalene triangle?

Alik [6]

There’s 180° in any triangle, so you can solve by doing 180-102-55= 78-55= 23° as our final answer.

5 0

3 years ago

Find the cosine of the angle between the planes −1x+3y+1z=0 and the plane 5x+5y+4z=−4

Zarrin [17]

Answer:

The he cosine of the angle between the planes is $\frac{14}{11\sqrt{6}}$ .

Step-by-step explanation:

Using the definition of the dot product:

$\cos\theta =\frac{\overrightarrow{a}\cdot \overrightarrow{b}}{|\overrightarrow{a}||\overrightarrow{b}|}$

The given planes are

$-1x+3y+1z=0$

$5x+5y+4z=-4$

The angle between two normal vectors of the planes is the same as one of

the angles between the planes. We can find a normal vector to each of the

planes by looking at the coefficients of x, y, z.

$\overrightarrow{n_1}=$

$\overrightarrow{n_2}=$

$\overrightarrow{n_1}\cdot \overrightarrow{n_2}=(-1)(5)+(3)(5)+(1)(4)=14$

$|n_1|=\sqrt{(-1)^2+(3)^2+(1)^2}=\sqrt{11}$

$|n_2|=\sqrt{(5)^2+(5)^2+(4)^2}=\sqrt{66}$

The cosine of the angle between the planes

$\cos\theta =\frac{\overrightarrow{n_1}\cdot \overrightarrow{n_2}}{|\overrightarrow{n_1}||\overrightarrow{n_2}|}$

$\cos\theta =\frac{14}{\sqrt{11}\sqrt{66}}$

$\cos\theta =\frac{14}{11\sqrt{6}}$

Therefore the cosine of the angle between the planes is $\frac{14}{11\sqrt{6}}$ .

5 0

3 years ago