Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
Step-by-step explanation:e equation has a leading coefficient of 1 or if the equation is a difference of squares. The zero-factor property is then used to find solutions. ... Another method for solving quadratics is the square root property. The variable is squared.
First you multiply 6(x) then you multiple 6(8)
Your equation should now look like this: 6x-48=72
Subtract 48 from both sides
Your equation should now look like 6x=120
Divide by 6
Answer is 20
Answer:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Step-by-step explanation:
The following information is missing in the question:
We have to find z-score for the given score on this dental anxiety scale: 12, 6
We are given the following information in the question:
Mean, μ = 11
Standard Deviation, σ = 4
We are given that the distribution of score is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
where x is the given score on this dental anxiety scale.
For x = 12
![z_{score} = \displaystyle\frac{12-11}{4} = 0.25](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7B12-11%7D%7B4%7D%20%3D%200.25)
For x = 6
![z_{score} = \displaystyle\frac{6-11}{4} = -1.25](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7B6-11%7D%7B4%7D%20%3D%20-1.25)