Alana has 12.5 cups of flour with which she is baking

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer:

Four times the amount of flour for the raisin bread plus 2.5 cups equals 12.5 cups total. The equation is 4x + 2.5 = 12.5. First, I subtract 2.5 from both sides, and then I divide both sides by 4. Each loaf contains 2.5 cups of flour.

This is the sample answer, I hope this helps.

almond37 [142]3 years ago

4 0

Answer:

12.5=4x+2.5 is the equation. First you would subtract 2.5 from both sides, leaving 10=4x. Then you divide by 4 and your answer would be x=2.5

Step-by-step explanation:

You might be interested in

The expression cos(A-B) - cos(A+B) is equal to

olchik [2.2K]

Cos (A-B) - cos (A+B)
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB

Ans: 4

6 0

3 years ago

Read 2 more answers

A ball is thrown upward with an initial velocity of 96 ft/sec from a height 640 ft. Its height h, in feet, after t seconds is

olchik [2.2K]

Check the picture below.

thus is at 0 = -16t² + 96t +640,

$\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40)
\\\\\\
0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t=
\begin{cases}
\boxed{10}\\
-4
\end{cases}$

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0

3 years ago

The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable X is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, β = 19 minutes.

The random variable X follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of X is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (X > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$