2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi
1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi
Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
Area Rectangle 2 = 280 mi * 170 mi = 47,600 mi²
Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²
Total Area = 6,400 mi² + 47,600 mi² + 9,800 mi² = <span>63,800 mi²</span>
Answer:
The solutions to the quadratic equations will be:
Step-by-step explanation:
Given the expression
Let us solve the equation by completing the square
Add (-6)² to both sides
simplify
Apply perfect square formula: (a-b)² = a²-2ab+b²
i.e.
so the expression becomes
solve
add 6 to both sides
Simplify
also solving
add 6 to both sides
Simplify
Therefore, the solutions to the quadratic equation will be:
2/5(x - 1) < 3/5(1 + x)
To find the solution, we can use the distributive property to simplify.
2/5x - 2/5 < 3/5 + 3/5x
Multiply all terms by 5.
2x - 2 < 3 + 3x
Subtract 2x from both sides.
-2 < 3 + x
Subtract 3 from both sides.
-5 < x
<h3><u>The value of x is greater than the value of -5.</u></h3>
Answer:
the answer is option B. angle S.
when naming an angle we place the vertex of the angle in the middle. here the angle is RST. But that option is unavailable. very often when there are no other angles interfering with the parent angle, we represent it using one letter that is the mid letter, the vertex. here in this case it is S.
