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svet-max [94.6K]

3 years ago

9

Answer: Alex is making a clock to give to his grandfather. To make the clock, he saws a slice of wood from a cylindrical log. Wh

at is the shape of the cross section of the log?

2 answers:

ss7ja [257]3 years ago

7 0

It would be circular since it was cut from a cylindrical log.

Hope This Helps You!
Good Luck Studying :)

Andru [333]3 years ago

7 0

Answer:

Circular

Step-by-step explanation:

You might be interested in

1. A waste management service attempts to design routes so that each of their trucks pick-up on average four tons of garbage or

IRINA_888 [86]

Answer:

1.-Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- p = 75 %

3.-3.-t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

Step-by-step explanation:

1.- If p-value is 0,04 and significance level α = 5 % or α = 0,05 then p-value < α

Test hypothesis should be ( x the average of garbage)

Null hypothesis H₀ x = 4 Tn

Alternative Hypothesis Hₐ x > 4 Tn

Then alternative hypothesis suggests a one tail-test to the right and

p-value < 0,05

Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- As we are dealing with a normal distribution the CI 95 % is symmetrical with respect to the mean, therefore the proportion of student living in Brooklyn is:

(0,73 + 0,77) /2

p = 0,75 p = 75 %

Test hypothesis:

Null Hypothesis H₀ μ = 26

Alternative Hypothesis Hₐ μ < 26

Alternative hypothesis tells us the test is a one-tail test to the left

Sample size n = 25

Sample mean μ = 24,4

Sample Standard deviation = 9,2

We assume normal distribution, and as n < 30 we use t-student table

with 24 degree of freedom

Significance level is 0,05 and df = 24 we find t (c) in t- student table

t(c) = 1,7109 test to the left t(c) = -1,7109

To calculate t(s)

t(s) = ( 24,4 - 26 ) / 9,2 / √25

t(s) = - 1,6 * 5 / 9,2

t(s) = - 0,87

Comparing t(s) and t(c) we have

t(s) > t(c)

t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

6 0

3 years ago

Hi how are you? :)<br><br> free points <3

bixtya [17]

Answer:

thank you

Step-by-step explanation:

can I get brainiest please

7 0

3 years ago

Read 2 more answers

NEED ASAP hurry plz<br><br>Write a story that would explain the graph below.

pishuonlain [190]

Answer:

A kid leaping happily to home after school

8 0

3 years ago

In △ABC, AB = 13.2m,

luda_lava [24]

Answer:

(i) ∠ABH = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)

46° + <HBC + 90 = 180°

<HBC+ 136° = 180°

subtract 136 from both-side of the equation

<HBC+ 136° - 136° = 180° -136°

<HBC = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

$\frac{sin A}{a}$ = $\frac{sin C}{c}$

A = ?

a=6.9

C=90

c=13.2

$\frac{sin A}{6.9}$ = $\frac{sin 90}{13.2}$

sin A = 6.9 sin 90 /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC + 121.5° = 180°

subtract 121.5° from both-side of the equation

<ABC + 121.5° - 121.5° = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

=58.5° - 44°

=14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180° ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB = 134°

Using sine rule,

$\frac{sin 134}{13.2}$ = $\frac{sin 14.5}{AH}$

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0

3 years ago

I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th

stellarik [79]

Answer:

The number of once is 9.1

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18 .........1

100 × H + 1 × O = 900 ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴ H = $\frac{882}{99}$

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e O = 18 - 8.9

∴ O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1 and The number of hundreds is 8.9

Answer

4 0

3 years ago