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3 years ago

URGENT HELP NEEDED! Brainliest! Please only correct answers...

Mathematics

2 answers:

hoa [83]3 years ago

6 0

I think it will be B.SAS

agasfer [191]3 years ago

5 0

I think that the answer would be D

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Question 5 help !! It’s worth 10 points !!!!

lesya692 [45]

Answer:

reason 4

Step-by-step explanation:

Division property of equality is when you divide both sides of an equation by the same nonzero number to get both sides equal.

for example;

20/4=20/4

5=5

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3 years ago

What is the surface area of the cone? (Use 3.14 for π.)

aev [14]

Answer: 117.226666667 cm^3

Step-by-step explanation:

So, we all know the formula for working out the volume of a cone is

V= 1/3πr^2h

V = 1÷3 x 3.14 × r^2 x h

The radius is half the diameter. Your diameter is 8 so the radius would be 4. And 7 is your height by the way.

So let's plot it all in!

V= 1÷3 x 3.14 × 4^2 x 7

V = 117.226666667cm^3

Round to the nearest 10 = 117.2cm^3

To the nearest 100 = 117.23cm^3

To the nearest whole number = 117cm^3

4 0

3 years ago

Read 2 more answers

ASAP please I will give you five stars

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

I think it's the 2nd one

7 0

3 years ago

Which of the following points are in the fourth quadrant of the xy-plane? Check all that apply.

Margaret [11]

Answer:

B and F

Step-by-step explanation:

The fourth quadrant contains a positive number for the x axis and a negative number for the y axis. (B=4,-5 and F=4,-7)

8 0

3 years ago

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

<em><u>The question is</u></em>

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

5 0

3 years ago