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Helga [31]
3 years ago
14

You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num

ber of dimes. Is your friend correct? Explain. Let d represent the number of dimes.
Mathematics
1 answer:
mart [117]3 years ago
6 0
Let x be the amount of quarters
Let y be the amount of dimes

X + 8 = y

Y + x = 2.80

Substitute

Y * x = 2.80

(X+8) + x = 2.80

2x = -6.80
x = -3.40

See this doesnr make sense
Because there cant be a negative amount of dimes
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Three women, Chantel, Marissa, and Qian, enjoy running laps around a circular track. Each women runs at a constant speed. It tak
lubasha [3.4K]

It takes 150 seconds for Qian to complete the track.

Let she runs the track in the clockwise direction.

In 60 seconds, she runs \frac{60}{150} = \frac{2}{5}th of the track.

Since she meets Marissa, who is running in the opposite (counter clockwise) direction in every 60 seconds, Marissa should have completed \frac{3}{5}th of the track.

Chantel meets Marissa in every 300 seconds.

So, in 60 seconds, she advances Marissa by \frac{1}{5}th of the track.

Hence, in 300 seconds, Qian, Marissa and Chantel all meets at the starting point.

ALITER;

Marissa meets Qian in every 60 seconds.

So, Marissa and Qian meet each other in 60th, 120th, 180th, 240th and 300th second.

But, it is given that Chantel meets Marissa in every 300 seconds.

So, in 300 seconds, Qian, Marissa and Chantel meet each other.

6 0
2 years ago
Select the point that is a solution to the system of inequalities​
ExtremeBDS [4]
<h3>Answer: B.  (-1, 0)</h3>

This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.  

In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality y \le x^2-3x true. So this is why we can rule choice A out.

Choice C is not a solution because (4,1) does not make y \le -x+3 true. This point is not below the red diagonal line. We can cross choice C off the list.

Choice D is similar to choice A, which is why we can rule it out as well.

5 0
3 years ago
12) The school that Danielle goes to is selling tickets to a choral performance. On the first day of
kicyunya [14]

Answer:

Senior citizen tickets = $9

Student tickets = $11

Step-by-step explanation:

We begin by converting these into simultaneous linear equation;

Senior citizen tickets = a

Student tickets = b

5a + 9b = 144

14a + 6b = 192

5a = 144 - 9b

a = 144/5 - 9b/5

a = 28.8 - 1.8b

We now substitute this into the first equation

14(28.8 - 1.8b) + 6b = 192

403.2 - 25.2b +6b = 192

-19.2b = 192 - 403.2

b = -211.2/-19.2

b = 11

Put the value of b into either equation

5a + 9b = 144

5a + 9(11) = 144

5a +99 = 144

5a = 144-99

5a = 45

a = 9

6 0
3 years ago
What is the most accurate representation of the area of a plot measuring 11.7 cm by 15.4 cm?
sergiy2304 [10]
In the given question the length and width of the plot are already given. although there is no direct specification regarding the one that is length or the one that is the width, so it can be taken as your own choice. This will not affect the ultimate answer. 
So
Area of the rectangular plot = Length * Width
                                             = 11.7 * 15.4 square cm
                                             = 180.18 square cm
So the area of the rectangular plot as can be seen from the above deduction is 180.18 square centimeter.
6 0
3 years ago
woodland Mound Park sells annual visitors passes for $12.50. Last year the park raised $53,500 in annual visitors pass sales. Ho
maria [59]

Answer:

4,280\ passes

Step-by-step explanation:

Let

x -----> the number of annual visitors pass sold

we know that

To find out the number of annual visitor passes sold, divide the total amount raised by the cost of a pass.

so

The linear equation that represent this problem is

12.50x=53,500

Solve for x

Divide by 12.50 both sides

x=\frac{53,500}{12.50}=4,280\ passes

5 0
3 years ago
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