His baby brother sleeps 21 hours.
There's a total of 24 hours in a day so you can divide by 8. That means 1/8 of the day is equal to 3 hours, so 7 times 3 hours equals 21 hours
Answer:
b
Step-by-step explanation:
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
Learn more about TRIANGLE here brainly.com/question/2217700
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(3x² -7x⁴) from (5x² - 3x⁸)
= 5x² - 3x⁸ - (3x² -7x<span>⁴ )
= </span> 5x² - 3x⁸ - 3x² + 7x<span>⁴
= </span>- 3x⁸ + 7x⁴ + 5x² <span>- </span><span>3x²
</span>
= - 3x<span>⁸ </span>+ 7x⁴ + 2x<span>²</span>
We can write the function in terms of y rather than h(x)
so that:
y = 3 (5)^x
A. The rate of change is simply calculated as:
r = (y2 – y1) / (x2 – x1) where r stands for rate
Section A:
rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)
rA = 12
Section B:
rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)
rB = 300
B. We take the ratio of rB / rA:
rB/rA = 300 / 12
rB/rA = 25
So we see that the rate of change of section B is 25
times greater than A
