Answer:
the solution is x = 2 and y = 4 OR (2,4)
Step-by-step explanation:
From the question
Equation 1: 3x-2y= -2
Equation 2: 3x + y = 10
Subtract equation 1 from equation 2, that is
3x + y = 10 - (3x -2y = -2)
You get
3x - 3x + y - (-2y) = 10 - (-2)
0 + y + 2y = 10 + 2
3y = 12
Divide both sides by 3
∴ y = 12/3
y = 4
Substitute the value of y into equation 2 to get x
3x + y = 10
3x + 4 = 10
Then,
3x = 10 - 4
3x = 6
Divide both sides by 3
∴ x = 6/3
x = 2
Hence, the solution is x = 2 and y = 4
Answer:
-1
Step-by-step explanation:
During a week:
Kevin works 3z during 5 days
kevin work (4z-7) during 1 day.
Kevin work 0 during 1 day.
z=unit time
f(z)= number of hours kevin works in one week.
f(z)=5(3z)+(4z-7)+0
f(z)=15z+4z-7
f(z)=19z-7
The number of hours kevin woirs in one week in terms of z is:
f(z)=19z-7
Answer:
B
Step-by-step explanation:
Given the 2 equations
4x + 3y = 16 → (1)
7x + 6y = 31 → (2)
Multiplying (1) by - 2 and adding to (2) will eliminate the term in y
- 8x - 6y = - 32 → (3)
Add (2) and (3) term by term
- x = - 1 ( multiply both sides by - 1 )
x = 1
Substitute x = 1 in either of the 2 equations and solve for y
Substituting in (1)
4(1) + 3y = 16
4 + 3y = 16 ( subtract 4 from both sides )
3y = 12 ( divide both sides by 3 )
y = 4
Solution is (1, 4 ) → B
Answer:
1 1/8
Step-by-step explanation:
