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julia-pushkina [17]
4 years ago
5

Galen sold tickets of his church’s carnival for a total of $2,820. Children’s tickets cost $3 each and adult tickets cost $5 eac

h. The number of children’s tickets sold was 30 more than 3 times the number of adult tickets slod. How many children’s ticket and how many adult tickets did he sell?
Mathematics
1 answer:
ycow [4]4 years ago
4 0

Answer:

615 children tickets

195 adults tickets

Step-by-step explanation:

Let the number of children’s tickets be c and the number of adult tickets be a.

Children’s ticket is $3 and adult’s is $5 for a total of $2,820. This means:

3c + 5a = 2,280

This is the first equation.

The number of children’s tickets sold is 30 more than 3 times that of the adults. This means

c = 3a + 30.

This is equation ii. We now substitute ii into I to yield:

3(3a+ 30) + 5a = 2,820

9a + 90 + 5a = 2,820

14a + 90 = 2,820

14a = 2820 - 90

14a = 2730

a = 2730/14 = 195 tickets

c = 3a + 30

c = 3(195) + 30 = 615

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