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mariarad [96]
3 years ago
6

Two eighths of a circle is what percentage

Mathematics
2 answers:
Andreas93 [3]3 years ago
4 0
25%

2/8=1/4
1/4=0.25
0.25=25%
vesna_86 [32]3 years ago
3 0
Two eighths of anything is 25% of it.
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Sec (a) + tan (a) = sec (a) – tan (a)
Mariulka [41]

Answer:

a = π n for n element Z

Step-by-step explanation:

Solve for a:

sec(a) + tan(a) = sec(a) - tan(a)

Subtract sec(a) - tan(a) from both sides:

2 tan(a) = 0

Divide both sides by 2:

tan(a) = 0

Take the inverse tangent of both sides:

Answer:  a = π n for n element Z

7 0
3 years ago
A = {red, green, blue, yellow} B = {orange, purple, black, blue} Find A U B.
Kipish [7]

Answer:

A∪B={   red , green , blue , yellow , orange , purple , black }

Step-by-step explanation:

Let A and B be two subsets Then A∪B represents the union of the two subsets which means that it consists of the elements present in A or B or in both A and B.

given A={ red , green , blue , yellow }

B={ orange , purple , black , blue }

Now A∪B={   red , green , blue , yellow , orange , purple , black }

for getting above first write all the elements in A then start writing elements of B and skip those elements of b which are already present in A and write all the elements of B.

8 0
3 years ago
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Find the area of the figure below?
inna [77]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Nataliya [291]

Two equations given. We have to find the solution sets for the equations.

y = -x²-2x+8 and y = 2x +11

There are 3 steps given. As both equations are equal to y, so we can equate the x parts.

-x²-2x+8 = 2x+11

0 = x²+4x+3

0 = (x+1)(x+3)

Now we have to use zero product property to solve this. If multiplication of two terms equal to 0, we can set each of them equal to 0.

x+1 = 0 , x+3 = 0

When, x+1 =0, by moving 1 to the other side we will get x = -1.

When x+3 =0, by moving 3 to the other side we will get x =-3

Now for the two values of x, we have to find y .

When x = -1, by plugging in the value to the second equation we will get,

y = 2x+11 = 2×(-1)+11 = -2 +11 = 9

So for x =-1, y =9.

The solution set is (-1, 9)

Now when x = -3, by plugging in the value to the second equation we will get,

y = 2x+11 = 2×(-3) +11 = -6+11 = 5

So for x = -3, y = 5

The solution set is (-3,5)

Therefore, the solutions for the system of equations are (-3, 5) and (-1, 9)

So the third option is correct.

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3 years ago
Which number can each term of the equation be multiplied by to eliminate the fractions before solving? 6 – x + = 6 minus StartFr
zheka24 [161]

Answer:

We need to multiply 12 to each term to eliminate fractions.

Step-by-step explanation:

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