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Gemiola [76]
3 years ago
8

A daily newspaper has 12135 subscribers when it began publication. Five years later it had 10090 subscribers. What is the averag

e yearly rate of change in the number of subscribers for the five-year period?
Mathematics
1 answer:
Marina CMI [18]3 years ago
3 0

Answer:

-409

Step-by-step explanation:

At the beginning - 12,135 subsribers,

Initial number of subsribers = 12,135

At the end - 10,090 subsribers

Final number of subsribers = 10,090

Time = 5 years.

So, the average yearly rate of change is

\dfrac{\text{Final number of subsribers}-\text{Initial number of subsribers}}{\text{Time}}\\ \\=\dfrac{10,090-12,135}{5}\\ \\=\dfrac{-2,045}{5}\\ \\=-409

The number of subscribers decreases by 409 per year

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3 years ago
Rewrite each statement using the appropriate mathematical language 1. There exists a number b belonging to the set B 2. Even num
Shtirlitz [24]

Answer:

1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻

Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

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J ≤ J⁻¹ : J ∈ Z⁻

4 0
3 years ago
A polynomial has one root that equals 5-7i. Name one other root of this polynomial
mezya [45]

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The other root is 5 + 7i.


4 0
3 years ago
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Everett made 3/5 of the baskets he shot suppose he shot 60 baskets how many did he make
givi [52]
As given he made  3/5 of basket he shot.

So we can find number of basket made by Everett equal to 3/5 of total number of shot .

So if total number of shot is 60.

Then the number of basket made by Everett = \frac{3}{5} of 60.
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So the number of basket made by Everett in 60 shots = 36.
3 0
3 years ago
Help me please fast ​
Natalija [7]

Answer:

Step-by-step explanation:

\frac{5}{x-3}+\frac{2}{x+1}=3  \\\\\frac{5(x+1)+2(x-3)}{(x-3)(x+1)} =3\\\\5x+5+2x-6=3(x-3)(x+1)\\\\7x-1=3(x^2+x-3x-3)\\\\7x-1=3(x^2-2x-3)\\\\7x-1=3x^2-6x-9\\\\0=3x^2-6x-7x-9+1\\0=3x^2-13x-8

Hence proved!

3 0
3 years ago
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