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lisabon 2012 [21]

4 years ago

8

Peter has $10 to spend at the fair. Write and solve an inequality to find how many rides Peter can go on if each ride costs $.75

.

1 answer:

professor190 [17]4 years ago

4 0

Answer:

$10=13 rides

Step-by-step explanation:

10 ÷ 0.75= 13.47, so $10=13 rides

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5x + 2y=7<br> - 2x + 6y=9

ollegr [7]

Answer:

x = $\frac{12}{17}$ or 0.706

$y = \frac{59}{34}$ or 1.735

Step-by-step explanation:

5x + 2y=7 ----->(eq 1)

- 2x + 6y=9 ----->(eq 2)

Multiply (eq 1) with 3

3×(5x + 2y) = 3×7

15x + 6y = 21 ----->(eq 3)

substract (eq 3) from (eq 2)

- 2x + 6y - (15x + 6y) = 9-21

- 2x + 6y - 15x - 6y = 9-21

- 2x - 15x + 6y - 6y = 9-21

-17x = -12

x = -12 ÷ -17

x = $\frac{12}{17}$

put x = $\frac{12}{17}$ in (eq 1)

$5*\frac{12}{17} + 2y = 7$

$2y = 7- 5*\frac{12}{17}$

$2y = \frac{7*17 - 60}{17}$

$2y = \frac{119- 60}{17}$

$2y = \frac{59}{17}$

$y = \frac{59}{17*2}$

$y = \frac{59}{34}$

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The answer is 0.675. 2700:4000 is a ratio that can be expressed as 2700/4000 = 27/40 = 0.675

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Step-by-step explanation:

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