Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
First to Answer
Answer:
The correct option is the third option. -2 1/4 / -2/3 = 3 3/8
-9/4 / -2/3 = 3 3/8
Answer:
the answer is 48, or the second choice B
Step-by-step explanation:
X intercept would mean plug in 0 for Y.
Then finding the y intercept would mean X is 0. Your answer will be 69420
volume of prism =area of Base ×height
