Complete Question
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.
Randomized Variables
vo 32.75 m/s
theta 32 degrees
What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?
Answer:
The horizontal distance is 
Explanation:
From the question we are told that
The initial velocity is 
The angle is 
The gravitational acceleration of the moon is 
Generally the distance traveled is mathematically represented as
=> 
=>
Answer:
30 C
Explanation:
Given:
Current flowing in the circuit (I) = 50 A
Start-up time (t) = 0.60 s
Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:
Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.
Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,
Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.
Answer:
14000 J / 0.40 J/s = 35 000 s or about 9.75 hrs
Answer
D) burning a candle
Explanation
When burning a candle no new substance is form.
We have both physical and chemical change occuring.
Physical part: Melting of the solid wax and evaporation of the liquid forms the physical change.
Chemical part: burning of the wax vapour forms the chemical change.
The 1st one is basically B because it will stay in motion with the same speed and in the same direction unless acted on by an unbalanced force and the 2cd one is A because most of is transformed into thermos energy. hope this helps!
