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bija089 [108]
3 years ago
7

Scavengers are organisms that help clean a habitat by feeding on dead or rotting flesh. They help break down the remains left be

hind by carnivores. Vultures and maggots (baby flies) are common scavengers.
Decomposers are organisms that break down the remains of dead animals or plants. Many live in or on the soil. Fungi and bacteria are examples of decomposers.

Which of the following is an example of decomposers at work?


a. a fish eating dead seaweed floating in the water
b. a vulture picking apart a dead mouse in the woods
c. a squirrel gnawing at a dead bird on the ground
d. a fungus growing on a rotten tomato, breaking down its skin
Physics
2 answers:
vagabundo [1.1K]3 years ago
6 0

Answer:

I think no B

if wrong correct me pls

have a nice day

#Captainpower

좋은 하루 되세요

#캡틴 파워

Julli [10]3 years ago
5 0

Answer: B

Explanation:

Vultures and maggots (baby flies) are common scavengers. Decomposers are organisms that break down the remains of dead animals or plants. ... Green plants are called producers because they take energy from sunlight and produce food in which the energy is stored.

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At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coeffi
Flura [38]

The given data is incomplete. The complete question is as follows.

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36.  Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

Explanation:

Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and \mu be the friction coefficient and m be the mass of car.

Hence, the given data is as follows.

                v = 0,     s = 84 m,     \mu = 0.36

According to Newton's law of second motion the expression for acceleration is as follows.

                      F = ma

                 -\mu N = ma

                 -\mu mg = ma

                      a = -\mu g

Also,    

               v^{2} = u^{2} + 2as

              (0)^{2} = u^{2} + 2(-\mu g)s

                  u^{2} = 2(\mu g)s

                            = \sqrt{2(0.36)(9.81 m/s^{2})(84 m)}

                            = 24.36 m/s

Thus, we can conclude that the speed of the car when the driver slammed on (and locked) the brakes is 24.36 m/s.

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