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2 years ago

In a hydroelectric dam the potential energy of lake water is transformed into _ energy as it begins to more.

Physics

2 answers:

Marianna [84]2 years ago

7 0

Answer:

mechanical energy

Explanation:

fenix001 [56]2 years ago

6 0

Mechanical energy I think

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Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.

SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

$\rho(r) = ar^2 - br^3$

r is the radius of the spherical shell

dr is the thickness

volume of shell

$dV = 4 \pi r^2 dr$

mass of shell

$dM = \rho(r)dV$

$\rho = \rho_0 - br$

now,

$dM = (\rho_0 - br)(4 \pi r^2)dr$

integrating both side

$M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr$

$M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})$

$M = \pi R^3(\dfrac{\rho_0}{3}+\rho)$

we know,

$a = \dfrac{GM}{R^2}$

$a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}$

$a =\pi RG(\dfrac{\rho_0}{3}+\rho)$

$a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)$

a = 9.94 m/s²

7 0

2 years ago

Can someone help me on these 4 questions pls?

irina1246 [14]

1-B. ... 2-C. ... 4-C. ... 5-A. ... 6-C.

3 0

3 years ago

A satellite of mass 1.02 metric tons orbits Earth at a constant height. If the mass of Earth is 6 x 10^24 kg,its radius is 6,360

xz_007 [3.2K]

Answer:

height = 1.5 x 10⁶ m = 1500 km

Explanation:

We can use the formula of gravitational force from the Newton's Gravitational Law:

$F = \frac{Gm_{1}m_{2}}{r^2}$

where,

F = Gravitational Force = 6.6 x 10³ N

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of earth = 6 x 10²⁴ kg

m₂ = mass of satellite = (1.02 tons)(1000 kg/1 ton) = 1.02 x 10³ kg

r = distance between center of earth and satellite = ?

Therefore, using these values in the equation, we get:

$6.6\ x\ 10^3\ N = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{r^2}\\\\r^2 = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{6.6\ x\ 10^3\ N}\\\\$

$r = \sqrt{61.84\ x\ 10^{12}\ m^2 }$

$r = 7.86\ x\ 10^6 m$

The distance between center of earth and the satellite is equal to the sum of height of satellite and radius of earth:

$r = height + radius\ of\ earth\\7.86\ x\ 10^6 m = height + 6.36\ x\ 10^6 m\\height = 7.86\ x\ 10^6 m - 6.36\ x\ 10^6 m$

<u>height = 1.5 x 10⁶ m = 1500 km</u>

4 0

2 years ago

Lisa was choosing between three alternatives: working on her job that pays her $60; writing a term paper which she values at $40

kow [346]

Opportunity cost is the amount of value that we need to forfeit/sacrifice in order to choose a certain decision.
In this case, the opportunit cost of choosing to go with friends would be:

($40 + $60) - $80

= $ 100 - $ 80

= $20

4 0

3 years ago

Four objects are situated along the y axis as follows: a 2.02 kg object is at 3.03 m, a 2.92 kg object is at 2.43 m, a 2.53 kg o

levacccp [35]

Answer:

0.975 m

Explanation:

The center of mass y = ∑m₁y₁/∑m₁ where m₁ = the individual masses and y₁ = the y - coordinates of the individual masses

So,

y = (2.02 kg × 3.03 m + 2.92 kg × 2.43 m + 2.53 kg × 0 m + 4.02 kg × -0.501 m)/(2.02 kg + 2.92 kg + 2.53 kg + 4.02 kg)

y = (6.1206 kgm + 7.0956 kgm + 0 kgm - 2.01402 kgm)/11.49 kg

y = 11.20218 kgm/11.49 kg

y = 0.975 m

So, the y- component of the center of mass of these objects is 0.975 m

8 0

2 years ago