
- Speed of the mobile = 250 m/s
- It starts decelerating at a rate of 3 m/s²
- Time travelled = 45s

- Velocity of mobile after 45 seconds

We can solve the above question using the three equations of motion which are:-
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.

We are provided with,
- u = 250 m/s
- a = -3 m/s²
- t = 45 s
By using 1st equation of motion,
⇛ v = u + at
⇛ v = 250 + (-3)45
⇛ v = 250 - 135 m/s
⇛ v = 115 m/s
✤ <u>Final</u><u> </u><u>velocity</u><u> </u><u>of</u><u> </u><u>mobile</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u> </u><u>m</u><u>/</u><u>s</u>
<u>━━━━━━━━━━━━━━━━━━━━</u>
A
method of procedure that has characterized natural science since the
17th century, consisting in systematic observation, measurement, and
experiment, and the formulation, testing, and modification of
hypotheses
Answer: Correct answer is B = 1.776933×
Explanation:
Given :
Moment of inertia I = 8.26×
kg
Mass of planet m = 6.54×
kg
Also, Planet is solid sphere so that, Moment of inertia is I =
m
=0.4m
Where R is radius of planet
Putting into calculation
We get,
I =
m
8.26×
= 0.4×6.54×
×
8.26×
= 2.616 
3.15749235×
= 
R = 1.776933×
Thus, Correct answer is B = 1.776933×
To find the rate of deceleration, subtract the initial velocity from the final velocity.