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Ber [7]
3 years ago
8

Triangle abc is an equilateral triangle with ac =6; find the area of this triangle.

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
The area of an equilateral triangle of side length "s" is
.. A = (√3)/4*s^2

Your triangle will have an area of
.. A = (√3)/4*6^2 = 9√3 . . . . . square units
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The sum of three consecutive counting numbers is 15 more than the greatest
Alex777 [14]

Answer:

9

Step-by-step explanation:

x+x+1+x+2 = 15+x+2

3x+3=x+17

3x=x+14

2x=14

x=7

7+8+9=24

9+15 = 24

7 0
3 years ago
Whats the factorization of <br> x2+3x−18
Alexeev081 [22]

Answer:

(X+6)x(X-3)

Step-by-step explanation:

X^2+6X-3X-18

Xx(X+6)-3(X+6)

(X+6)x(X-3)

big X is the variable

small x is multiplication sign

4 0
2 years ago
Pig is a dice game where each player during their turn rolls a 6-sided die. if the player rolls a 2 through 6, they decide wheth
dexar [7]
Blow your mind eh d
4 0
3 years ago
When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav
pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • If Z > 2, the result is considered <u>significantly high</u>.

If np \geq 10 and n(1-p) \geq 10, the binomial distribution can be approximated to the normal with:

\mu = np

\sigma = \sqrt{np(1-p)}

In this problem:

  • 943 peas, thus, n = 943
  • 3/4 probability of being red, thus p = \frac{3}{4} = 0.75.

Applying the approximation:

\mu = np = 943(0.75) = 707.25

\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297

Item a:

Using continuity correction, this probability is P(X \geq 717 - 0.5) = P(X \geq 716.5), which is <u>1 subtracted by the p-value of Z when X = 716.5</u>.

Then:

Z = \frac{X - \mu}{\sigma}

Z = \frac{716.5 - 707.25}{13.297}

Z = 0.7

Z = 0.7 has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0
2 years ago
Whoever can solve this prob will get a very special reward! Math prob: Put parentheses on 3 + 6 x 5 divided by 2 - 7 to make the
liraira [26]

Answer:

(3+6*5)/2-7

Step-by-step explanation:

3 0
3 years ago
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