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Lostsunrise [7]
4 years ago
10

Solve for u -6 = 6+3u

Mathematics
2 answers:
Pachacha [2.7K]4 years ago
4 0

Answer:

- 4

Step-by-step explanation:

Step 1:

- 6 = 6 + 3u    Equation

Step 2:

- 12 = 3u     Subtract 6 on both sides

Step 3:

- 12 ÷ 3   Divide

Answer:

x = - 4

Hope This Helps :)

NemiM [27]4 years ago
3 0
U = -4

Work:
-6 = 6 + 3u
-12 = 3u
-4 = u
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Please help with this, i tried to solve for x, and it didnt give me any of those answers
Firdavs [7]
I hope this helps you




4.1+4. (-x)+2x=3.x+3.1



4-4x+2x=3x+3


-2x-3x=3-4


-5x= -1


x=1/5
3 0
3 years ago
Find the perimeter of a rectangle that is 3 inches long and 4 inches wide.
katen-ka-za [31]

Answer:

14 inches

Step-by-step explanation:

Perimeter of a rectangle

= 2(l + w)

Given length L = 3 inches and

Width w = 4 inches

Perimeter = 2(3 + 4)

Simplify the bracket

2 x 7

14 inches

4 0
4 years ago
Read 2 more answers
Which function represents a vertical stretch of an exponential function?
nika2105 [10]

Answer:

A. f(x)=3(\frac{1}{2})^x

Step-by-step explanation:

The options are:

A. f(x)=3(\frac{1}{2})^x\\\\B. f(x)=\frac{1}{2}(3)^x\\\\C. f(x)=(3)^{2x}\\\\ D. f(x)=3^{(\frac{1}{2}x)}

For this exercise it is important to remember that, by definition, the Exponential parent functions have the form shown below:

f(x) = a^x

Where "a" is the base.

There are several transformations for a function f(x), some of those transformations are shown below:

1. If  bf(x) and  b>1, then the function is stretched vertically by a factor of "b".

2. If   bf(x)  and 0, then the function is  compressed vertically by a factor of "b"

Therefore, based on the information given above, you can identify that the function that represents a vertical stretch of an Exponential function, is the one given in the Option A. This is:

f(x)=3(\frac{1}{2})^x

Where the factor is:

b=3

And 3>1

7 0
3 years ago
Read 2 more answers
What is the factored form of x^3 -1
lianna [129]

Answer:

The factored form of x^3 -1 will be:

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

Step-by-step explanation:

Given the expression

x^3-1

Rewrite 1 as 1³

=x^3-1^3

\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

            =\left(x-1\right)\left(x^2+x+1\right)

Thus, the factored form of x^3 -1 will be:

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

8 0
3 years ago
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