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Ulleksa [173]
3 years ago
11

two places A and B are 80km apart on a highway. Two cars at A and B, when moving in the same direction meet in 8 hours and when

moving towards each other, meet in 1 hour 20 minutes. Find the speed of the two cars

Mathematics
2 answers:
Inessa [10]3 years ago
4 0

Answer:

va= 35 km/hr vb=25 km/hr

watch explanation

SIZIF [17.4K]3 years ago
4 0
Va=35km/hr vb=25 km/hr
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20. In the image, ABC has measure 58°. What is the measure of ABD?
PolarNik [594]

Answer:

Option B, 29°

Step-by-step explanation:

The diagram is a angle bisecting diagram which divides the 58° angle into two 29° angles.

Answered by GAUTHMATH

3 0
2 years ago
Read 2 more answers
Rewrite the fractions 3/4 and 5/16 as fractions with a least common denominator.
nata0808 [166]

Answer:

12/16 and 5/16

Step-by-step explanation:

We are given two fractions with denominator 4 and 16.

To find the least common denominator, of 4 and 16.

Factorise 4 and 16.

4 = 2x2  

16 = 2x2x2x2

i.e. 4 divides 16.

Hence  Least common denominator = bigger number = 16

Make the given fractions to equivalent fractions with common denominator 16.

3/4 = 4(3)/4(4) = 12/16 and

5/16 = 1(5)/16(1)= 5/16

Hence answer would be

12/16 and 5/16


6 0
2 years ago
Read 2 more answers
What is the answer some one help please!!
scoray [572]
The correct answer is B
4 0
3 years ago
What is the value of x
irga5000 [103]

Answer:

X=24

Step-by-step explanation:

1. (4x + 11) + (3x + 1) = 180 (Combine like terms)

2. 7x + 12 = 180 (Subtract 12 from both sides)

3. 7x = 168 (Divide both sides by 7)

4. x = 24

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
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