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Kay [80]
3 years ago
11

What is the height of this cone?

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

\sqrt{12^2-6^2} = √108 = 6√3

Step-by-step explanation:

zavuch27 [327]3 years ago
4 0
Ohhhh Time for some Pythagorean theorem
A^2+B^2=C^2

So if you fill in the variables

A^2+6^2=12^2
Solve that and get
A^2+36=144
Now
Solve a^2=108
square root 108 is your answer
If you have any questions just ask
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How do you solve f-3/4=5/6?
gulaghasi [49]

Answer:

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Step-by-step explanation:

f-3/4=5/6

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f =38

6 0
2 years ago
The value of the definite integral / 212x – sin(x) dx / 122x-sin(x) is
blondinia [14]

Hi there!

\boxed{= 70 + cos(12) - cos(2) \approx 71.26}

\int\limits^{12}_{2} {x-sin(x)} \, dx

We can evaluate using the power rule and trig rules:

\int x^n = \frac{x^{n+1}}{n+1}

\int x = \frac{1}{2}x^{2}

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Therefore:

\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}

Evaluate:

(\frac{1}{2}(12^{2})+cos(12)) - (\frac{1}{2}(2^2)+cos(2))\\= (72 + cos(12)) - (2 + cos(2))\\\\= 70 + cos(12) - cos(2) \approx 71.26

3 0
3 years ago
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gladu [14]

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Step-by-step explanation:

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Step-by-step explanation:

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