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Nady [450]
3 years ago
6

8. A steel ball rolls from rest down a ramp with an acceleration of -3 m/s/s. What is its velocity after rolling for 5 s?

Physics
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

C. -15m/s

Explanation:

using formula, v = u + at

where v = final velocity

u = initial velocity = 0

a = acceleration = -3m/s/s

t = time = 5sec

=> v = 0 + -3×5 = -15m/s

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When catching a baseball, the ball applies a force of 39.6 N to a  catcher's glove.  If the work done on the catchers glove is 4
cricket20 [7]

Answer:

d = 1.19 m

Explanation:

Given that,

The force applied by the ball, F = 39.6 N

The work done on the catchers glove is 47.5 J

We need to find the distance traveled by the ball. We know that,

Work done, W = Fd

Where

d is the distance traveled

d=\dfrac{W}{F}\\\\d=\dfrac{47.5 }{39.6 }\\\\d=1.19\ m

So, it will cover 1.19 m.

4 0
3 years ago
True or False: The rock cycle is a slow process.
IrinaK [193]
<span>The rock cycle is a slow process is true </span>
8 0
2 years ago
Read 2 more answers
Suppose that 2 J of work are needed to stretch a spring from its natural length of 30 cm to a length of 42 cm. How far (in cm) b
sergeinik [125]

A distance of 10.8 cm beyond its natural length will a force of 30 N keep this spring stretched

<u>Explanation:</u>

Work, W = 2 J

Initial distance, x_{1} = 30 cm

Final distance,  = 42 cm

Force, F = 30 N

Stretched length, x = ?

We know,

W = 1/2 kΔx²

Δx = 42-30 cm = 12 cm = 0.12 m

2 J = 1/2 k X (0.12)²

k = 277.77 N/m

According to Hooke's law,

F = kx

30 N = 277.77 X x

x = 0.108 m

x = 10.8  cm

A distance of 10.8 cm beyond its natural length will a force of 30 N keep this spring stretched.

7 0
2 years ago
A horizontal disk with a radius of 23 m rotates about a vertical axis through its center. The disk starts from rest and has a co
lys-0071 [83]

Answer:

time is 0.42 sec

Explanation:

Given data

radius = 23 m

angular acceleration = 5.7 rad/s²

to find out

time

solution

we know that radius is constant so that

tangential acceleration At = angular acceleration × radius   ............. 1

tangential acceleration =  5.7 × 23 = 131.1 m/s²

and

radial acceleration Ar =  (angular velocity)² × radius    ........................2

we consider angular velocity = ω

this is acting toward center

so

compare 1 and 2

At = Ar

5.7 r =ω³ r

ω = √5.7 = 2.38746 rad/s

so

ω = 5.7 t

2.387 = 5.7 t

t =  2.387 / 5.7

t = 0.4187

time is 0.42 sec

8 0
3 years ago
For this study, the researcher is analyzing data by using __________ measures. A. experimental B. qualitative C. quantitative D.
DiKsa [7]

Answer:

B. qualitative

Explanation:

Since in the question it is mentioned that it takes the teacher opinion with respect to the student lunchroom that arranged the opinion in four classifications and according to that the report is also written

So this research represents the quality of the data collected as it does not specify the rating in terms of liking the student lunchroom

Therefore the correct option is B. qualitative

7 0
3 years ago
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