The three parts of the ear anatomy are the outer ear, the middle ear
and the inner ear. The inner ear is also called the cochlea. (‘Cochlea’
means ‘snail’ in Latin; the cochlea gets its name from its distinctive
coiled up shape.)
The outer ear consists of the pinna, ear canal and eardrum
The middle ear consists of the ossicles (malleus, incus, stapes) and ear drum
The inner ear consists of the cochlea, the auditory (hearing) nerve and the brain
Sound waves enter the ear canal and make the ear drum vibrate. This
action moves the tiny chain of bones (ossicles – malleus, incus, stapes)
in the middle ear. The last bone in this chain ‘knocks’ on the membrane
window of the cochlea and makes the fluid in the cochlea move. The
fluid movement then triggers a response in the hearing nerve.
or
<span>Sound waves enter the ear canal and make the ear drum vibrate. This action moves the tiny chain of bones (ossicles – malleus, incus, stapes) in the middle ear. The last bone in this chain 'knocks' on the membrane window of the cochlea and makes the fluid in the cochlea move.
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Answer:
Avogadro's law.
Explanation:
Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.
Mathematically,
V n
V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;
K = mathematical constant.
The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.
V 1/P at constant temperature (Boyle’s law)
V T at constant pressure ( Charles’law)
V n at constant temperature and pressure ( Avogadro’s law )
Combining the equations yields,
V nT/P
Introducing a constant,
V = nRT/P
PV = nRT
Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1
To solve this problem it is necessary to apply the kinematic equations of motion and Hook's law.
By Hook's law we know that force is defined as,
Where,
k = spring constant
x = Displacement change
PART A) For the case of the spring constant we can use the above equation and clear k so that
Therefore the spring constant for each one is 11876.92/2 = 5933.46N/m
PART B) In the case of speed we can obtain it through the period, which is given by
Re-arrange to find \omega,
Then through angular kinematic equations where angular velocity is given as a function of mass and spring constant we have to
Therefore the mass of the trailer is 4093.55Kg
PART C) The frequency by definition is inversely to the period therefore
Therefore the frequency of the oscillation is 0.4672 Hz
PART D) The time it takes to make the route 10 times would be 10 times the period, that is
Therefore the total time it takes for the trailer to bounce up and down 10 times is 21.4s
The disturbance does not have a specific motions
