The maximum amount of work performed is

Explanation:
The efficiency of a real heat engine is given by the equation:
(1)
where
is the temperature of the cold reservoir
is the temperature of the hot reservoir
However, the efficiency of a real heat engine can be also written as:

where
is the maximum work done
is the heat absorbed from the hot reservoir
can be written as

where
is the heat released to the cold reservoir
So the previous equation can be also written as
(2)
By combining eq.(1) and (2) we get

And re-arranging the equation and solving for
, we find

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Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.
Given :
A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg.
To Find :
The embankment in the height.
Solution :
Since no external force is acting in the system, therefore total energy will be conserved.
Initial kinetic energy of the object = Energy stored in spring

Also, initial potential energy is 0.
Now,

Therefore, the embankment height is 0.64 m.
Answer:
0.69 g/cm^3
Explanation:
Given that a small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79mL.
The volume of the frog will be:
79 - 50 = 29mL
Convert it to litre by dividing it by 1000
29/1000 = 0.029 L
Since 1L = 1000 cm^3
Convert it to cm^3 by multiplying it by 1000
0.029 × 1000 = 29 cm^3
Density = mass/volume
Substitute the mass and volume into the formula
Density = 20/29
Density = 0.6896 g/cm3
Therefore, the density of the frog is 0.69 g/cm^3 approximately
Answer:
His performance would improve
Explanation:
This is because, he now has a larger distance to cover in the 10.0 ft diameter circle. This increased distance would cause him to give a greater angular speed to his whirl and thus a greater tangential velocity to the shot put. This greater speed would thus cause the shot put to travel more in the 10.0 ft diameter circle throw than in the 7 ft 6 in diameter circle throw.