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aniked [119]
3 years ago
13

Select all of the characteristics associated with freshwater ponds. (Click multiple answers)

Physics
1 answer:
Wewaii [24]3 years ago
7 0

Answer: The signs of a well-balanced pond include healthy fish, clear water, thriving plants, and minimal pests such as algae.

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A common practice in cooking is the addition of salt to boiling water (Kb = 0.52 °C kg/mole). One of the reasons for this might
lozanna [386]

Answer:

640.59 g of NaCl.

Explanation:

Using Boiling point elevation,

ΔTb = kb * i * b

Where,

b = molality

kb = 0.52 °C kg/mole

i = van't koff factor

ΔTb = ΔTsol - ΔTsolv

= 2°C

2 = 0.52 * b

= 3.846 mol/kg.

Mass of water, solvent = 2.85 kg

Molality is the ratio of the number of moles of the solute to the mass of the solvent.

= 3.846 * 2.85

= 10.96 mol.

Mass of NaCl = molar mass * number of moles

= 58.44 * 10.96

= 640.59 g of NaCl.

5 0
3 years ago
A 96.0 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on
Ede4ka [16]

Answer:

The work done by the hoop is equal to 5.529 Joules.

Explanation:

Given that,

Mass of the hoop, m = 96 kg

The speed of the center of mass, v = 0.24 m/s

To find,

The work done by the hoop.

Solution,

The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,

K_i=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

I is the moment of inertia, I=mr^2

Since, \omega=\dfrac{v}{r}

K_i=mv^2

K_i=96\times (0.24)^2=5.529\ J

Finally it stops, so the final energy of the hoop will be, K_f=0

The work done by the hoop is equal to the change in kinetic energy as :

W=K_f-K_i

W = -5.529 Joules

So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.

4 0
3 years ago
True or False. Alfred Wegener contributed greatly to the theory of plate tectonics by collecting and analyzing fossil, glacial a
bearhunter [10]

Answer:

The Answer would be True

Explanation:

8 0
2 years ago
Read 2 more answers
An object is released from rest and falls a distance h during the first second of time. How far will it fall during the next sec
Viefleur [7K]

Answer:

E. 3h

Explanation:

We know that

u = 0 m/s.

velocity after t = 1s

v = u+gt = 0+9.81 x 1s= 9.81 m/s

distance covered in 1st sec

= =>> ut+0.5 x g x t²

=>>0 + 0.5x 9.81 x 1 = 4.90m

Let 4.90 be h

distance travelled in 2nd second will now be used

So velocity after t = 1s

=>>1 x t+ 0.5 x g x t²

=>9.81x 1 + 0.5 x 9.81 x 1 = 3 x 4.90

So since h= 4.90

Then the ans is 3x h = 3h

3 0
3 years ago
Please select the word from the list that best fits the definition
My name is Ann [436]

Answer:

glycolysis is the answer to the question

7 0
3 years ago
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