Answer:
The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Explanation:
Given that,
Wavelength of red = 660 nm
Wavelength of blue = 470 nm
Separated d= 0.30 mm
Distance between screen and slits D= 5.0 m
We need to calculate the distance for red wavelength
Using formula for distance
Where, D = distance between screen and slits
d = separation of slits
Put the value into the formula
For blue wavelength,
Put the value into the formula again
We need to calculate the distance on the screen between the first-order bright fringes for each wavelength
Using formula for distance
Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Answer:
10 N.m
Explanation:
Force * Perpendicular distance.
= 20 N * 0.5 m
= 10 N.m
Answer:
a) The velocity of rock at 1 second, v = 9.8 m/s
b) The velocity of rock at 3 second, v = 29.4 m/s
c) The velocity of rock at 5.5 second, v = 53.9 m/s
Explanation:
Given data,
The rock is dropped from a bridge.
The initial velocity of the rock, u = 0
a) The velocity of rock at 1 second,
Using the first equation of motion
v = u + gt
v = 0 + 9.8 x 1
v = 9.8 m/s
b) The velocity of rock at 3 second,
v = u + gt
v = 0 + 9.8 x 3
v = 29.4 m/s
c) The velocity of rock at 5.5 second,
v = u + gt
v = 0 + 9.8 x 5.5
v = 53.9 m/s
Answer:
vector of zero magnitude
Explanation:
The displacement is a vector magnitude, therefore, in addition to being a module, it has direction and sense.
In this case it moved 350 m and then returned the same 350 m, so the total displacement is zero.
If we draw the vector, one has a directional direction to the right and the other direction to the left, therefore when adding the two vectors gives a vector of zero magnitude
Answer:
Explanation:
Given:
- mass of car,
- distance of skidding after the application of brakes,
- coefficient of kinetic friction,
<u>So, the energy dissipated during the skidding of car:</u>
<em>Frictional force:</em>
where N = normal reaction by ground on the car
<em>Now from the work-energy equivalence:</em>
is the dissipated energy.
