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Serga [27]
3 years ago
10

A town has a population of 15000 and grows at 4.5% every year. To the

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Answer:

In 8 years the population will reach 35900.

Step-by-step explanation:

Given : A town has a population of 15000 and grows at 4.5% every year.

To find : How long will it be until the population will reach 35900?

Solution :

The population growth can be identified by using N=N_oe^{rt}

Where,

N=35900 is future population

N_o=15000 is the initial population

t is the time taken

4.5%=0.045 is the rate of the growth

Rephrasing the formula to get the value of t,

t=\frac{log(\frac{N}{N_0})}{r}

Substituting the values,

t = \frac{log(\frac{35900}{15000})}{0.045}

t = \frac{log(2.393)}{ 0.045}

t = \frac{0.3789}{ 0.045}

t =8.42

t\approx 8

Therefore, In 8 years the population will reach 35900.

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The Jacobys drove 19 1/2 hours from Monday to Thursday.

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Abi is carrying 3 gallons of milk. Each gallon of milk weighs 8.6 pounds. Abi wants to know the total weight of milk he is carry
Vesna [10]

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25.8 pounds

Step-by-step explanation:

3 x 8.6 = 25.8

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3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

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What is 347500 rounded to the nearest 1000
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vampirchik [111]

Answer:

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Step-by-step explanation:

|-11.02| - |-9.91|  (First solve in absolute)

11.02 - 9.91        (any values outside absolute becomes positive)

1.11=Ans

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