Answer:
Step-by-step explanation:
What is the VALUE OF 3r=10+5 when r=10?
substitute 10 for r in 3r=10+5. We get:
3(10) = 10 + 5, or 30 = 15. This equation is FALSE when r = 10.
You could solve the equation for r, however:
3r=10+5 becomes 3r = 15, and so r = 5. 5 is a solution; 10 is not a solution.
Answer:
1) B 2) A 3) B 4) A 5) D
Step-by-step explanation:
I did all this mentally, so if you needed work im sorry ;-;
Answer:
Step-by-step explanation:
It's two unequal real solutions.
a = 1
b = 7
c = 6
discriminate = sqrt(7^2 - 4*1*6)
discriminate = sqrt(49 - 24)
discriminate = sqrt(25)
discriminate = 5
Now you cannot determine what this means unless you put it in the quadratic formula
x = (-7 +/- 5)/2
x = (- 7 + 5) / 2
x = - 2/2 = - 1
x = (-7 - 5)/2
x = -12/2
x = - 6
You see that you have two unequal reals.
0 means u do not move right or left at all and the 4 means u move up 4 units.
