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3 years ago

What is 347500 rounded to the nearest 1000

Mathematics

1 answer:

Annette [7]3 years ago

5 0

It is 348000 because if its 5 or above it rounds up and 4 or below rounds down so the 5 rounds the 7 to an 8

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Pls help. 2 steps.................

elena-14-01-66 [18.8K]

Answer:

Where?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

At 3:00 pm the temperature in Pittsburgh was 93 degrees Fahrenheit decreased at a rate of 2 degrees Fahrenheit every 30 minutes.

elixir [45]

The answer is 76 degrees

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3 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

$= 0.92 -0.24\\\\= 0.68$

6 0

3 years ago

A picture frame can hold a Photograph that is 16 inches long and 12 inches wide. What is the area of the photo that fits the fra

TEA [102]

Answer:

16x12=192

Step-by-step explanation:

Two times sixteen equals thirty two, ten times sixteen equals one hundred sixty, thirty two plus one hundred sixty equals one hundred ninety two

8 0

3 years ago

Someone help me please

miss Akunina [59]

Answer:

Option D is the correct option.

Step-by-step explanation:

Given: 3 boxes with volumes 1331 , 1331 , 729

To find : Height of stacked boxes

$h {1}^{3} = 1331 = h1 = \sqrt[3]{1331} = 11$

$h {2}^{3} = 1331 = h2 = \sqrt[3]{1331} = 11$

$h {3}^{3} = 729 = h3 = \sqrt[3]{729} = 9$

Now,

$h = h1 + h2 + h3$

$= 11 + 11 + 9$

$= 31$

Hope this helps...

Good luck on your assignment...

3 0

3 years ago