If α and β are the Roots of a Quadratic Equation ax² + bx + c then :
✿ Sum of the Roots : α + β 
✿ Product of the Roots : αβ 
Let the Quadratic Equation we need to find be : ax² + bx + c = 0
Given : The Roots of a Quadratic Equation are 6 and 3
⇒ α = 6 and β = 3
Given : The Leading Coefficient of the Quadratic Equation is 4
Leading Coefficient is the Coefficient written beside the Variable with Highest Degree. In a Quadratic Equation, Highest Degree is 2
Leading Coefficient of our Quadratic Equation is (a)
⇒ a = 4
⇒ Sum of the Roots 
⇒ -b = 9(4)
⇒ b = -36
⇒ Product of the Roots 
⇒ c = 18 × 4
⇒ c = 72
⇒ The Quadratic Equation is 4x² - 36x + 72 = 0
In my school, we do congruent statements with triangles by using SSS,ASA, SAS, etc.
For the first one, it would be SSS because the side-side-side matches up with side-side-side.
For the second one, I believe they are not similar because the lengths are corresponding between the two triangles.
Hope this helps! :)
If you need any help on triangle congruency statements, I have a flip-booklet we made in our geo class that helps a lot, and I would love to send it to you!
Here: m = 6, b = 4.
m is the slope of the line, so slope is 6.
any line parallel to this line will also have the slope of 6.
any line perpendicular to the given line will have the slope of: -1/m1<span>.
hope this helps leave a thanks if it does </span>
Answer:
Step-by-step explanation:
Using quadratic formula
we will have two solutions.
2x^2 - x - 4 = 0
So, a=2 b=-1 c=-4, we have:
Finally, we have two solutions:
