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jasenka [17]
3 years ago
5

A tin man has a head that is a cylinder with a cone on top. the height of the cylinder is 12 inches and the height of the cone i

s 6 inches. the radius of both the cylinder and the cone is 4 inches. what is the volume of the tin man's head in terms of pi?
a.192π in3
b.224π in3
c.384π in3
d.912π in3

Mathematics
2 answers:
Rashid [163]3 years ago
4 0
I am attaching solution... Enjoy!

lisov135 [29]3 years ago
3 0
I believe your answer is b.
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Math:
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Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

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x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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Answer:

Correct answer is B

Step-by-step explanation:

hope it helps ^^

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When you plug in the numbers for the integers, you get
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